Respuesta :
Answer:
(We already know that: x -1/x-1 = 1 and x + 1/x + 1 = 1 there is no need of keeping them)
(x-1/x-1) x+5/x+1 -x-2/x-1(x+1/x+1)
= x + 5/x + 1 - x - 2/x - 1
= x²/x + 5/x + x/x - x²/x - 2/x - x/x
= x² + 5 + x - x² - 2 - x
= 5 -2
= 3
This is the solution of given equation [tex]\frac{x^4-2x^3 +2x^2+3x-6}{x^2-x}[/tex]
What is equation?
Equation is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is equal.
[tex](x-\frac{1}{x} -1) x+\frac{5}{x} +1 -x-\frac{2}{x-1}+ (x+\frac{1}{x}+1)[/tex]
[tex](x^2-1 -x) +\frac{5}{x} +1 -x+ (x+\frac{1}{x}+1)-\frac{2}{x-1}[/tex]
[tex]x^2 +\frac{5}{x} +1 -x+ \frac{1}{x}-\frac{2}{x-1}[/tex]
[tex]x^2-x +1 +\frac{6}{x} -\frac{2}{x-1}[/tex]
[tex]\frac{(x^2-x +1)x(x-1) +6(x-1)-2x}{x(x-1)}[/tex]
[tex]\frac{x^4-2x^3 +2x^2+3x-6}{x^2-x}[/tex]
Hence, this is the solution of given equation [tex]\frac{x^4-2x^3 +2x^2+3x-6}{x^2-x}[/tex]
Learn more about equation
https://brainly.com/question/13947055
#SPJ2
