Respuesta :

luisejr77

Answer:

[tex]x=3\\y=-4[/tex]

Step-by-step explanation:

Subtract both equations:

[tex](7x+2y)-(-x+2y)=13-(-11)[/tex]

Distribute the negative signs and then you need to add the like terms:

[tex]7x+2y+x-2y=13+11\\8x=24[/tex]

 BY the division prperty of equality, divide both sides of the equation by 8:

[tex]\frac{8x}{8}=\frac{24}{8}\\x=3[/tex]

Substitute the value of x obtained into any of the original equations to find the value of y. Then you get:

[tex]7x+2y=13\\7(3)+2y=13\\21+2y=13\\2y=-8\\y=-4[/tex]

kudzordzifrancis
ANSWER

The solution is

x=3, y=-4

EXPLANATION

We were given two equations in two variables.

First equation:

[tex]7x + 2y = 13[/tex]

Second equation:

[tex] - x + 2y = - 11[/tex]

Subtract the second equation from the first equation:

[tex](7x - - x) + (2y - 2y) = 13 - - 11[/tex]

This gives us,

[tex]7x + x + 0= 13 + 11[/tex]

[tex]8x= 24[/tex]

Divide both sides by 8.

[tex]x = \frac{24}{8} [/tex]

[tex]x = 3[/tex]

Put x=3 into the first equation:

[tex]7(3) + 2y = 13[/tex]

[tex]21 + 2y = 13[/tex]

Group similar terms;

[tex]2y = 13 - 21[/tex]

[tex]2y = - 8[/tex]

Divide both sides by 2,

[tex]y = \frac{ - 8}{2} = - 4[/tex]

The solution is

x=3, y=-4

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