Application of exponential and logarithm functions. Round to hundredth.

You deposit $1000 in a bank account. If the account pays 3.5% annual interest compounded quarterly,
a) find the balance after 3 years.
b) how many years are needed to make the balance $5000

Respuesta :

Answer:

a) $1110.20

b) 46.18 years

Step-by-step explanation:

We must apply the exponential formula for the calculation of annual compound interest problems

The formula is:

[tex]P = P_0(1 + r) ^ t[/tex]

Where P is the profit after t years

[tex]P_0[/tex] is the initial investment

r is the interest rate.

So in this problem, we have the quarterly interest rate.

We want to find the balance after 3 years. If in a year there are 4 quarters, then in 3 years there are t = 12 quarters.

a) To find the balance we substitute [tex]P_0 = 1000[/tex], [tex]t = 12[/tex] quarters, [tex]r = \frac{0.035}{4}[/tex]

[tex]P = 1000(1 + \frac{0.035}{4}) ^ {12}\\\\P = \$1110.20[/tex]

b) We must calculate t necessary to make the balance of 5000

[tex]5000 = 1000(1 + \frac{0.035}{4}) ^ {4t}\\\\5 = (1 + \frac{0.035}{4}) ^ {4t}\\\\5 = (1.00875) ^ {4t}\\\\log(5) = 4tlog(1.00875)\\\\t = \frac{log(5)}{4log(1.00875)}\\\\t =\ 46.18 years[/tex]