Find the surface area of the composite solid.
A.
680 in.2
B.
800 in.2
C.
920 in.2
D.
1,040 in.2

The ends of the rectangle = 10*10*2 = 200
The long sides and bottom of the rectangle = 12*10*3 = 360
Vertical end of the triangle = 5*10 = 50
The sides of the triangle = 12*5*1/2*2 = 60
Triangle slope = 13*10 = 130
Total = 200 + 360 + 50 + 60 + 130 =
800 in sq
Answer:
Option B. 800 in²
Step-by-step explanation:
We have to find the surface area of the composite solid.
This solid is made up of two solids, Rectangular prism and a right angle triangular prism.
Now we will calculate surface area separately.
Surface area of rectangular prism = 2(lw + hl + hw)
But one side of lw is hidden so formula will be = 2(lw +hl + hw) - lw
where h = height = 10 in
w = width = 12 in
l = length = 10 in
Surface area of rectangular prism = 2(10×12 + 10×10 + 10×12) - 10×12
= 2(120 + 100 + 120) - 120
= 2(340) - 120 = 560 in²
Surface area of right angle triangular prism = 2(Rectangle sides)+ 2(triangular sides)
Surface area of triangular prism = 5×10 + 13×10 + 2([tex]\frac{1}{2})(5)(12)[/tex]
= 50 + 130 + 60
= 240 in²
Now total surface area of the composite solid = surface area of rectangular prism + surface area of triangular prism
= 560 + 240 = 800 in²
Therefore, option B. 800 in² is the answer.