Answer:
The length of the second base is [tex]15\ in[/tex]
Step-by-step explanation:
we know that
The area of a trapezoid is equal to
[tex]A=\frac{1}{2}(b1+b2)h[/tex]
where
b1 is the length of the first base
b2 is the length of the second base
h is the height of the trapezoid
In this problem we have
[tex]b1=8\ in[/tex]
[tex]h=13\ in[/tex]
[tex]A=149.5\ in^{2}[/tex]
substitute and solve for b2
[tex]149.5=\frac{1}{2}(8+b2)(13)[/tex]
[tex]299=(8+b2)(13)[/tex]
[tex]299/13=(8+b2)[/tex]
[tex](8+b2)=23[/tex]
[tex]b2=23-8=15\ in[/tex]
