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What is the electric force acting between two charges of 0.0042 C and −0.0050 C that are 0.0030 m apart?


A. −2.1 1010 N
B. 2.1 1010 N
C. 6.3 107 N
D. −6.3 107 N

Respuesta :

Answer:

A.−2.1 × 10^10 N

Explanation:

Using the formula;

E = k Q1Q2/d²

Where;

E is the electrical force  

k is the constant  

Q1, Q2 are the two charges  and

d is the distance between the two charges

Therefore;

E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²  

 = -2.1 x 10^10 N

Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.

snoopy1420

Answer:

-2.1x10^10 N

Explanation:

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