First, you need to find the area of the triangle
[tex](6 \times 8) \div 2 = 24 {ft}^{2} [/tex]
Then, Find the Area of the circle and divide it in half (you have only a semicircle). So you need the radius, that is half of the diameter= 4ft
[tex] {4}^{2} \times 3.1 = 16 \times 3.1 = 49.6{ft}^{2} [/tex]
Divide it in half (for the semicircle)
[tex]49.6 \div 2 = 24.8 {ft}^{2} [/tex]
Sum the area of the triangle and the area of the semicircle
[tex]24 + 24.8 = 48.8 {ft}^{2} [/tex]
I hope you're satisfied (and i Hope I'm right)
