Answer:
The original width of the rectangle is [tex]\frac{4}{5}\ ft[/tex]
Step-by-step explanation:
Let
x-----> the length of the rectangle
y----> the original width of the rectangle
we know that
[tex]\frac{7}{25}=x(y-\frac{1}{3})[/tex]
we have
[tex]x=\frac{3}{5}\ ft[/tex]
substitute the value ox x and solve for y
[tex]\frac{7}{25}=\frac{3}{5}(y-\frac{1}{3})[/tex]
[tex]\frac{7}{15}=(y-\frac{1}{3})[/tex]
[tex]y=\frac{7}{15}+\frac{1}{3}=\frac{12}{15}\ ft[/tex]
Simplify
[tex]y=\frac{12}{15}=\frac{4}{5}\ ft[/tex]
