contestada

the equations of three lines are given below.
line 1: 3y = -4x + 4
line 2: 6x + 8y = 6
line 3: y = - 4 / 3 x - 7
the fraction is negative
for each pair of lines, determine whether they are parallel, perpendicular, or neither.
line 1 and line 2: parallel, perpendicular, or neither
line 1 and line 3: parallel, perpendicular, or neither
line 2 and line 3: parallel, perpendicular, or neither

Respuesta :

kudzordzifrancis

ANSWER

line 1 and line 2: neither

line 1 and line 3 : parallel

line 2 and line 3: neither

EXPLANATION

The equation of line 1 is

3y = -4x + 4

We rewrite in slope intercept form to get:

[tex]y = - \frac{4}{3} x + \frac{4}{3} [/tex]

The slope is

[tex]m1 = - \frac{4}{3} [/tex]

The second line is:

6x + 8y = 6

We rewrite in slope intercept form to get,

[tex]y = - \frac{3}{4} x + \frac{3}{4} [/tex]

The slope is

[tex]m2 = - \frac{3}{4} [/tex]

The third line is

[tex]y = - \frac{4}{3} x - 7[/tex]

[tex]m3 = - \frac{4}{3} [/tex]

line 1 and line 2: are neither parallel nor perpendicular because the two slope s are not the same and their product is not -1.

line 1 and line 3 are parallel because their slopes are the same

[tex]m1 = m3 = - \frac{4}{3} [/tex]

line 2 and line 3:are neither parallel nor perpendicular because the two slopes are not the same and their product is not -1.