Respuesta :
4x² - 12x = 7
- 7 - 7
4x² - 12x - 7 = 0
4x² + 2x - 14x - 7 = 0
2x(2x) + 2x(1) - 7(2x) - 7(1) = 0
2x(2x + 1) - 7(2x + 1) = 0
(2x - 7)(2x + 1) = 0
2x - 7 = 0 or 2x + 1 = 0
+ 7 + 7 - 1 - 1
2x = 7 2x = -1
2 2 2 2
x = 3¹/₂ or x = ⁻¹/₂
- 7 - 7
4x² - 12x - 7 = 0
4x² + 2x - 14x - 7 = 0
2x(2x) + 2x(1) - 7(2x) - 7(1) = 0
2x(2x + 1) - 7(2x + 1) = 0
(2x - 7)(2x + 1) = 0
2x - 7 = 0 or 2x + 1 = 0
+ 7 + 7 - 1 - 1
2x = 7 2x = -1
2 2 2 2
x = 3¹/₂ or x = ⁻¹/₂
First subtract 7 from each side of the equation.
4x^2 - 12x - 7 = 0.
Now we can substitute terms into our friend the quadratic equation, which you should memorize. Or we can try a few simple factors. 7 is prime, so to make -7 one number must be positive and one must be negative.
The first pair I tried, (2x + 1)(2x - 7) yield a middle term of -12x. Therefore, setting each to zero yields: x = -1/2, or x = 7/2.
4x^2 - 12x - 7 = 0.
Now we can substitute terms into our friend the quadratic equation, which you should memorize. Or we can try a few simple factors. 7 is prime, so to make -7 one number must be positive and one must be negative.
The first pair I tried, (2x + 1)(2x - 7) yield a middle term of -12x. Therefore, setting each to zero yields: x = -1/2, or x = 7/2.