Answer:
The area of the original square is [tex]36\ m^{2}[/tex]
Step-by-step explanation:
Let
x------> the length side of the original square
we know that
[tex]99=(x+5)(x+3)\\ \\99=x^{2} +3x+5x+15\\ \\x^{2} +8x+15-99=0\\ \\ x^{2} +8x-84=0[/tex]
Solve the quadratic equation by graphing
The solution is [tex]x=6\ m[/tex]
see the attached figure
The area of the original square is
[tex]A=6^{2}=36\ m^{2}[/tex]
