For this case we have the following expression:
[tex]\frac {80} {h}[/tex]
We substitute a small number h, that is, [tex]h = 0.05[/tex]
So:
[tex]\frac {80} {0.05} = 1600[/tex]
It is observed that the value of the expression is very large, that is, it increases with small values of h
We substitute a large number h, that is, [tex]h = 500[/tex]
So:
[tex]\frac {80} {500} = 0.16[/tex]
It is observed that the value of the expression decreases.
Answer:
The value of the given expression decreases when h increases from a small positive number to a large positive number.
