A gas station has a cylindrical fueling tank that holds the gasoline for its pumps, as modeled below. The tank holds a maximum of 20,000 gallons of gasoline and has a length of 34.5 feet.

A metal pole is used to measure how much gas is in the tank.

To the nearest tenth of a foot, how long does the pole need to be in order to reach the bottom of the tank and still extend one foot outside the tank?

[1 ft^3=7.48 gallons ]

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znk

Answer:

[tex]\boxed{ \text{10.9 ft}}[/tex]

Step-by-step explanation:

The formula for the volume of a cylinder is

V = πr²h

Data:

V = 20 000 gal

h = 34.5 ft

Calculations:

I assume the gasoline tank is lying on its side, so we are asked to find the diameter of the tank.

(a) Convert the volume to cubic feet

V= 20 000 gal × (1 ft³/7.48 gal) = 2674 ft³

(b) Calculate the radius of the tank

V = πr²h

r² = V/(πh) = 2674/(π × 34.5) = 24.67 ft²

r = √24.67 = 4.967 ft

(c) Calculate the diameter of the tank

d = 2r = 9.934 ft

(d) Calculate the length of the measuring pole

l = d + 1 = 9.934 + 1 = [tex]\boxed{ \textbf{10.9 ft}}[/tex]

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The length of the pole is 10.93 feet if the gas station has a cylindrical fueling tank that holds the gasoline for its pumps.

What is a cylinder?

In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.

We know the volume of the cylinder is given by:

[tex]\rm V = \pi r^2 h[/tex]

We have volume of the tank V = 20,000 gallons

In ft³

V = 2673.796 ft³

And h = 34.5 feet

2673.796 = (3.14)(r)²(34.5)

After calculating, we get:

The radius r = 4.96 feet

The diameter = 2r = 2(4.96) = 9.93 feet

Pole length = 1 + 9.93 = 10.93 feet

Thus, the length of the pole is 10.93 feet if the gas station has a cylindrical fueling tank that holds the gasoline for its pumps.

Learn more about the cylinder here:

brainly.com/question/3216899

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