A conductor carrying a conventional current in the positive-x direction is in a magnetic field whose vector points in the positive-y direction. A force on the conductor will be in the:

positive-z direction (out of the screen)

negative-z direction (into the screen)

negative-y direction

negative-x direction

Magnetic force is given by [tex]F = il \wedge B[/tex]. A quick way to gauge the components is to put your left middle finger on the direction of the current, your index on the direction of the magnetic field, and the thumb gives you the answer you want.

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aristocles aristocles · Answer 2 · 2019-06-15T10:43:18+02:00

Answer:

positive-z direction (out of the screen)

Explanation:

As we know that length vector of the current carrying conductor is always along the direction of conventional current

So here direction of length vector will be + X direction

magnetic field is along + Y direction

now we will have

[tex]\vec F = I(\vec L \times \vec B)[/tex]

now we will have

[tex]\vec F = ILB(\hat i \times \hat j)[/tex]

[tex]\vec F = ILB\hat k[/tex]

so magnetic force will be along +Z direction (out of the screen)