Respuesta :
Answer:
[tex]\boxed{\text{16 ft}}[/tex]
Step-by-step explanation:
h(x) = -2x² + 4x + 16
At the time the ball is thrown,
x = 0
h(0) = -2 × 0² + 4 × 0 + 16 = [tex]\boxed{ \textbf{16 ft}}[/tex]
Answer:
[tex]\boxed{\text{16 ft}}[/tex]
Step-by-step explanation:
h(x) = -2x² + 4x + 16
At the time the ball is thrown,
x = 0
h(0) = -2 × 0² + 4 × 0 + 16 = [tex]\boxed{ \textbf{16 ft}}[/tex]