Write an equation in standard form of an ellipse that has a vertex at (0,6), and a co-vertex at (1,0), and an center at the origin

Question

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Ashraf82 Ashraf82 · Answer 1 · 2019-05-21T06:21:25+02:00

Answer:

The standard form of the equation of the ellipse is x² + y²/36 = 1

Step-by-step explanation:

* Lets revise the standard equation of the ellipse

- The standard form of the equation of an ellipse with

center (0 , 0) is x²/b² + y²/a² = 1

, where

* the length of the major axis is 2a

* the coordinates of the vertices are (0 , ±a)

* the length of the minor axis is 2b

* the coordinates of the co-vertices are (±b , 0)

* the coordinates of the foci are (0 , ± c), where c² = a² - b²

* Now lets solve the problem

∵ The vertex of the ellipse is (0 , 6)

∴ a = 6

∵ The co-vertex is (1 , 0)

∴ b = 1

∵ the center is the origin (0 , 0)

∵ The standard form equation is x²/b² + y²/a² = 1

∴ x²/(1)² + y²/(6)² = 1 ⇒ simplify

∴ x² + y²/36 = 1

* The standard form of the equation of the ellipse is x² + y²/36 = 1

kudzordzifrancis kudzordzifrancis · Answer 2 · 2019-05-21T06:23:45+02:00

ANSWER

[tex]\frac{ {y}^{2} }{ 36 } + \frac{ {x}^{2} }{ 1} = 1[/tex]

EXPLANATION

The equation of an ellipse in standard form with vertices on the y-axis and center at the origin is given by:

[tex] \frac{ {y}^{2} }{ {a}^{2} } + \frac{ {x}^{2} }{ {b}^{2} } = 1[/tex]

where

a=6 and b=1

We plug in these value into the formula to get:

[tex]\frac{ {y}^{2} }{ {6}^{2} } + \frac{ {x}^{2} }{ {1}^{2} } = 1[/tex]

[tex]\frac{ {y}^{2} }{ 36 } + \frac{ {x}^{2} }{ 1} = 1[/tex]