Respuesta :
(a) Both the girl and the boy have the same nonzero angular displacement.
Explanation:
The angular displacement of an object moving in uniform circular motion, as the boy and the girl on the merry-go-round, is given by
[tex]\theta= \omega t[/tex]
where
[tex]\omega[/tex] is the angular speed
t is the time interval
For a uniform object in uniform circular motion, all the points of the object have same angular speed. This means that the value of [tex]\omega[/tex] is the same for the boy and the girl.
Therefore, if we consider the same time interval t, the boy and the girl will also have same nonzero angular displacement.
(b) The girl has greater linear speed.
Explanation:
The linear (tangential) speed of a point along the merry-go-round is given by
[tex]v=\omega r[/tex]
where
[tex]\omega[/tex] is the angular speed
r is the distance of the point from the centre of the merry-go-round
In this problem, the girl is near the outer edge, while the boy is closer to the centre: since the value of [tex]\omega[/tex] is the same for both, this means that the value of r is larger for the girl, so the girl will also have a greater linear speed.
Both the girl and the boy riding on a merry-go-round have the same nonzero angular displacement, and the girl has greater linear speed.
What is angular displacement?
The angular displacement of a body is the product of the angular velocity of the body and the time taken by it. It can be given as,
[tex]\theta=\omega\times t[/tex]
Here, (ω) is the angular velocity and (t) is the time taken.
The girl and the boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center.
- Part A) The rider which has greater angular displacement-
Each point of the circular motion, has the same angular speed and therefor the same angular displacement for the same time.
Hence, for a given elapsed time interval, both the girl and the boy have the same nonzero angular displacement.
- Part B-The greater linear speed-
A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center.
As the linear speed is the product of angular velocity and distance of the body from the center of the rotation.
As the girl is at more distance from the center compare to boy. Hence, the girl has greater linear speed.
Learn mote about the angular displacement here;
https://brainly.com/question/13572778
