Answer:
D. [tex]19units^{2}[/tex]
Step-by-step explanation:
We can modeling this problem as two rectangles, The first one in the left of the image as a rectangle with base [tex]b_{1} =8units[/tex] and height [tex]h_{1} =2units[/tex], and the second one in the right bottom of the image as a rectangle with base [tex]b_{2} = 5units - 2 units=3units[/tex] (the diference of 5units - 2 units is the base of the second rectangle) and height [tex]h_{2} =1unit[/tex].
The area of rectangle is [tex]a=bxh[/tex]
Calculating the area of each rectangle.
Rectangle 1 [tex]a_{1} =8unitsx2units=16units^{2}[/tex]
Rectangle 2 [tex]a_{2} =3unitsx1unit=3units^{2}[/tex]
So, in order to calculate the total area of the polygon shown in the image.
[tex]a_{total} =a_{1} +a_{2} \\a_{total} =16units^{2} +3units^{2} \\a_{total} =19units^{2}[/tex]
