Respuesta :

Answer:

A

Step-by-step explanation:

Given sinP = [tex]\frac{5}{13}[/tex] = [tex]\frac{opposite}{hypotenuse}[/tex]

Then the right triangle has a hypotenuse of 13 and a leg 5

Use Pythagoras' identity to find the other leg x ( adjacent)

x² + 5² = 13²

x² + 25 = 169 ( subtract 25 from both sides )

x² = 144 ( take the square root of both sides )

x = [tex]\sqrt{144}[/tex] = 12 , hence

tanP = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{5}{12}[/tex]

The value of the tanP when sin is equal to 5/13  is 5/12.

We have given that,

[tex]sinP = \frac{5}{13}[/tex]

What is the formula for the sin ratio?

[tex]sin(\theta)=\frac{Opposite}{hypogenous}[/tex]

Then the right triangle has a hypotenuse of 13 and a leg of 5

Use Pythagoras' identity to find the other leg x ( adjacent)

x² + 5² = 13²

x² + 25 = 169 ( subtract 25 from both sides )

x² = 144 ( take the square root of both sides )

taking square root on both sides

[tex]x=\sqrt{144} \\x=12[/tex]

Therefore we get the value of the tanP.

[tex]tanP = \frac{opposite }{adjucent} = \frac{5}{12}[/tex]

Therefore the value of the tanP is 5/12.

To learn more about the trigonometric ratio visit:

https://brainly.com/question/24349828

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