⇛{5(√7+√5)}/2.
Step-by-step explanation:
Given,
5/(√7-√5)
The denominator is √7-√5.
We know that
The rationalising factor of √c-√a is √c+√a.
Therefore, the rationalising factor of √7-√5 is √7+√5. To rationalise the denominator of 5/(√7-√5), we multiply this by (√7+√5)/(√7+√5).
⇛{5/(√7-√5)}/{(√7+√5)/(√7+√5)}
⇛{5(√7+√5)}/{(√7-√5)(√7+√5)}
⇛{5(√7+√5)}/{(√7)²-(√5)} [∵ (a-b)(a+b)=a²-b²]
⇛{5(√7+√5)}/{(√7*7)-(√5*5)}
⇛{5(√7+√5)}/(7-5)
⇛{5(√7+√5)}/2
Hence, the denominator is rationalised.
Read more:
Similar Question;
rationalise the denominator 1/√20..
https://brainly.com/question/19473806?referrer
