contestada

11.
♡
What is the standard form of the equation of a circle with center (3,-2) and radius 4?
AO (X - 3)2 + (y + 2)2 = 16
BO (x – 3)2 + (y + 2)2 = 4
C. (x + 3)2 + (y – 2)2 = 16
D. (x – 3)2 + ( – 2)2 = 16​

Respuesta :

Luv2Teach

Answer:

(x-3)^2+(y+2)^2=16

Step-by-step explanation:

The standard form of a circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where h and k are the coordinates of the center and r is the radius, which is squared.  From our information, h is 3--> (x-3) and k is -2--> (y-(-2))--> (y+2) and 4 squared is 16.  Your choice is A.

nemo010405

Answer:

(x-3)^2+(y+2)^2=16

Step-by-step explanation:

The standard form of a circle is  

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where h and k are the coordinates of the center and r is the radius, which is squared.  From our information, h is 3--> (x-3) and k is -2--> (y-(-2))--> (y+2) and 4 squared is 16.  Your choice is A.

Otras preguntas