Answer:
p(A) = 0.55
p(b) = 0.45
Step-by-step explanation:
Experimental probability = [tex]\frac{Number of favorable outcomes}{Total number of outcomes}[/tex]
total students = 55 + 45 ⇒ 100
let A be the probability that students brought lunch from house = [tex]\frac{55}{100}[/tex] ⇒ 0.55
let B be the probability that students order school lunch = [tex]\frac{45}{100}[/tex] ⇒ 0.45
