Answer: Option 'A' is correct.
Step-by-step explanation:
Since we have given that
√72-3×√12+√192
As we have
[tex]\sqrt{72}=6\sqrt{2}[/tex]
[tex]\sqrt{12}=6\sqrt{2}[/tex]
[tex]\sqrt{192}=8\sqrt{3}[/tex]
So, our equation becomes
[tex]6\sqrt{2}-3\times 2\sqrt{3}+8\sqrt{3}\\\\=6\sqrt{2}-6\sqrt{3}+8\sqrt{3}\\\\=6\sqrt{2}+2\sqrt{3}[/tex]
Hence, Option 'A' is correct.
