contestada

The limit of sqrt(9x^4 + 1)/(x^2 - 3x + 5) as x approaches infinity is


[tex]\displaystyle\lim_{x \to \infty} \frac{\sqrt{9x^4+1}}{x^2 -3x + 5}[/tex]


(A) 1

(B) 3

(C) 9

(D) nonexistent

Respuesta :

Answer:

B. 3.

Step-by-step explanation:

At the limit we can take the numerator  to be √(9x^4) = 3x^2

The function is of the form ∞/ ∞ as x approaches ∞ so we can apply l'hopitals rule:

Differentiating top and bottom we have   6x / 2x - 3. Differentiating again we get 6 / 2 = 3.

Our limit as x  approaches infinity  is 3.

Otras preguntas