Respuesta :
1) Static friction coefficient: 0.355
The crate is initially at rest. The crate remains at rest until the horizontal pushing force is less than the maximum static frictional force.
The maximum static frictional force is given by
[tex]F_s = \mu_s mg[/tex]
where
[tex]\mu_s[/tex] is the static coefficient of friction
m = 21 kg is the mass of the crate
g = 9.8 m/s^2 is the acceleration due to gravity
The horizontal force required to set the crate in motion is 73 N: this means that this is the value of the maximum static frictional force. So we have
[tex]F_s=73 N[/tex]
Using this information into the previous equation, we can find the coefficient of static friction:
[tex]\mu_s = \frac{F}{mg}=\frac{73 N}{(21 kg)(9.8 m/s^2)}=0.355[/tex]
2) Kinetic friction coefficient: 0.267
Now the crate is in motion: this means that the kinetic friction is acting on the crate, and its magnitude is
[tex]F_k = \mu_k mg[/tex] (1)
where
[tex]\mu_k[/tex] is the coefficient of kinetic friction
There is a horizontal force of
F = 55 N
pushing the crate. Moreover, the speed of the crate is constant: this means that the acceleration is zero, a = 0.
So we can write Newton's second law as
[tex]F-F_k = ma = 0[/tex]
And by substituting (1), we can find the value of the coefficient of kinetic friction:
[tex]F-\mu_k mg = 0\\\mu_k = \frac{F}{mg}=\frac{55 N}{(21 kg)(9.8 m/s^2)}=0.267[/tex]
The coefficients of static and kinetic friction between the crate and floor are;
μ_s = 0.3547
μ_k = 0.2672
1) To find the coefficient of static friction, is given by the formula;
F_s = μ_s*mg
We are given;
Mass; m = 21 kg
Horizontal force to set it to motion; F_h = 73 N
Now, in this static friction equation, we are using this force of 73 N because static friction is friction at rest and 73 N is the force to pull the object from rest. Thus;
73 = μ_s(21 × 9.8)
μ_s = 73/(21 × 9.8)
μ_s = 0.3547
2) To find the coefficient of kinetic friction, is given by the formula;
F_k = μ_k*mg
We will make use of the force of 55N because we are dealing with friction associated with motion and 55N is the force that keeps the object in motion. Thus;
μ_k = F_k/(mg)
μ_k = 55/(21 × 9.8)
μ_k = 0.2672
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