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The table shows ten random samples from two potato fields that were fertilized with two different fertilizers. Based on the mean of the data sets, which statement is true?

A) Fertilizer A produced a 15% greater yield

B) Fertilizer B produced a 15% greater yield

C) Fertilizer A produced a 3.0% greater yield

D) Fertilizer B produced a 3.0% greater yield

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nathaniel12 nathaniel12 · Answer 1 · 2019-05-31T15:50:57+02:00

Answer:

Fertilizer B produced a 15% greater yield

Step-by-step explanation:

Mean yield fertilizer A = 20.2

Mean yield fertilizer B = 23.2

Thus, 23.2 − 20.2

20.2

= 0.1485 ≈ 0.15 or 15%

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Alleei Alleei · Answer 2 · 2020-01-13T10:29:17+01:00

Answer : The correct option is, (B) Fertilizer B produced a 15% greater yield

Step-by-step explanation :

First we have to calculate the total yield of potato with fertilizer A.

Total yield of potato with fertilizer A = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) kg

Total yield of potato with fertilizer A = 202 kg

Now we have to calculate the total yield of potato with fertilizer B.

Total yield of potato with fertilizer B = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) kg

Total yield of potato with fertilizer B = 232 kg

Now we have to calculate the percent yield.

[tex]\text{Percent yield}=\frac{232-202}{202}\times 100[/tex]

[tex]\text{Percent yield}=14.85\% \approx 15\%[/tex]

From this we conclude that, the fertilizer B produced a 15% greater yield.

Hence, the correct option is, (B) Fertilizer B produced a 15% greater yield