Answer:
[tex]4.8\cdot 10^{-15} N[/tex]
Explanation:
The force exerted on a charged particle by an electric field is:
[tex]F=qE[/tex]
where
q is the magnitude of the charge of the particle
E is the magnitude of the electric field
For an electron,
[tex]q=1.6\cdot 10^{-19} C[/tex]
while the magnitude of the electric field in the problem is
[tex]E=30000 V/m[/tex]
so, the electric force on the electron is
[tex]F=(1.6\cdot 10^{-19}C)(30000 V/m)=4.8\cdot 10^{-15} N[/tex]