Respuesta :
Answer:
[tex]\boxed{ x = \frac{3}{2}}[/tex]
Step-by-step explanation:
[tex]\begin{array}{rcll}4 - 2(6x - 5) & = & -4 &\\- 2(6x - 5) & = & -8 &\text{Subtracted 4 from each side}\\6x - 5 & = & 4 &\text{Divided each side by -2}\\6x & = & 9 &\text{Added 5 to each side}\\x & = &\mathbf{\frac{3}{2}} &\text{Divided each side by 6}\end{array}[/tex]
Check:
[tex]\begin{array}{rlc}4 - 2(6\times\frac{3}{2} - 5)& = &-4\\4 - 2(9 - 5) & = & -4\\4 - 2\times4 & = & -4\\4 - 8 & = & -4\\-4 & = & -4\\\end{array}[/tex]
Answer:
[tex]\large\boxed{x=\dfrac{3}{2}}[/tex]
Step-by-step explanation:
[tex]4-2(6x-5)=-4\qquad\text{subtract 4 from both sides}\\\\-2(6x-5)=-8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(-2)(6x)+(-2)(-5)=-8\\\\-12x+10=-8\qquad\text{subtract 10 from both sides}\\\\-12x=-18\qquad\text{divide both sides by (-12)}\\\\x=\dfrac{-18\!\!\!\!\!\diagup^3}{-12\!\!\!\!\!\diagup_2}\\\\x=\dfrac{3}{2}[/tex]