Answer:
Option B. [tex]11.78\ in^{3}[/tex]
Step-by-step explanation:
we know that
The volume of a cone is equal to
[tex]V=\frac{1}{3} \pi r^{2}h[/tex]
we have
[tex]r=1.5\ in[/tex]
[tex]h=5\ in[/tex]
substitute
[tex]V=\frac{1}{3} \pi (1.5)^{2}(5)[/tex]
[tex]V=3.75\pi\ in^{3}[/tex]
assume
[tex]\pi =3.14[/tex]
[tex]V=3.75(3.14)=11.78\ in^{3}[/tex]
