contestada

Match each quadratic equation with its solution set.
2x2 − 32 = 0
4x2 − 100 = 0
x2 − 55 = 9
x2 − 140 = -19
2x2 − 18 = 0
{-8, 8}
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{-4, 4}
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{-5, 5}
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{-11, 11}
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Respuesta :

2x2-32=0 is -4,4

4x2-100=0 is -5,5

For this case we solve each of the equations:

[tex]2x ^ 2-32 = 0[/tex]

Adding 32 to both sides of the equation:

[tex]2x ^ 2 = 32[/tex]

Dividing between 2 on both sides of the equation:

[tex]x ^ 2 = \frac {32} {2}\\x ^ 2 = 16[/tex]

Applying square root to eliminate the exponent:

[tex]x = \pm \sqrt {16}\\x = \pm4\\x_ {1} = + 4\\x_ {2} = - 4[/tex]

Second equation:

[tex]4x ^ 2-100 = 0[/tex]

Adding 100 to both sides of the equation:

[tex]4x ^ 2 = 100[/tex]

Dividing between 4 on both sides of the equation:

[tex]x ^ 2 = \frac {100} {4}\\x ^ 2 = 25[/tex]

Applying square root to eliminate the exponent:

[tex]x = \pm \sqrt {25}\\x = \pm5\\x_ {1} = + 5\\x_ {2} = - 5[/tex]

Third equation:

[tex]x ^ 2-55 = 9[/tex]

Adding 55 to both sides of the equation:

[tex]x ^ 2 = 9 + 55\\x ^ 2 = 64[/tex]

Applying square root to eliminate the exponent:

[tex]x = \sqrt {64}\\x = \pm8[/tex]

Fourth equation:

[tex]x ^ 2-140 = -19[/tex]

Adding 140 to both sides of the equation:

[tex]x ^ 2 = -19 + 140\\x ^ 2 = 121[/tex]

Applying square root to eliminate the exponent:

[tex]x = \pm \sqrt {121}\\x = \pm11[/tex]

Fifth equation:

[tex]2x ^ 2-18 = 0[/tex]

Adding 18 to both sides of the equation:

2x ^ 2 = 18

Dividing between 2 on both sides of the equation:

[tex]x ^ 2 = \frac {18} {2}\\x ^ 2 = 9[/tex]

Applying square root to eliminate the exponent:

[tex]x = \pm \sqrt {9}\\x = \pm3[/tex]

Answer:

[tex]2x ^ 2-32 = 0, x_ {1} = + 4, x_ {2} = - 4\\4x ^ 2-100 = 0, x_ {1} = + 5, x_ {2} = - 5\\x ^ 2-55 = 9, x_ {1} = + 8, x_ {2} = - 8\\x ^ 2-140 = -19, x_ {1} = + 11, x_ {2} = - 11\\2x ^ 2-18 = 0, x_ {1} = + 3, x_ {2} = - 3[/tex]