If BP PC, what is m BC?
60
90
180

Answer: 90
Step-by-step explanation:
Given: A circle with center P and B and C are two points on circle such that
BP is perpendicular to PC, it gives [tex]\angle{BPC}=90^{\circ}[/tex]
We know that in a circle, the degree measure of an arc is equal to the measure of the central angle that intercepts the arc.
Therefore, the measure of [tex]\overarc{BC}[/tex]= Central angle made by [tex]\overarc{BC}[/tex].
⇒ the measure of [tex]\overarc{BC}=90^{\circ}[/tex]