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At a temperature of 500 kelvins, 6 liters of an ideal gas had a pressure of 300 newtons
per square meter. If the temperature was reduced to 250 kelvins, and the volume raised
to 9 liters, what was the resulting pressure ?
(A) 100 newtons/m^2
(B) 150 newtons/m^2
(C) 450 newtons/m^2
(D) 900 newtons/m^2
(E) none of these

Respuesta :

Answer A

Explanation:

sebassandin

Answer:

(A) 100 newtons/m^2

Explanation:

Hello,

In this case, the equation defining such changes is:

[tex]P_1V_1T_2=P_2V_2T_1[/tex]

Thus, the unknown is the pressure at the second state, which is found as shown below:

[tex]P_2=\frac{P_1V_1T_2}{V_2T_1}=\frac{300Pa*6L*250K}{9L*500K} \\P_2=100Pa=100\frac{N}{m^2}[/tex]

Therefore, the answer is (A).

Best regards.

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