Given that (Triangle)MNO is similar to (Triangle)RST, determine the perimeter of (Triangle)RST.

Answer:
C
Step-by-step explanation:
Given that the 2 triangles are similar then the ratios of corresponding sides are equal.
This enables RT to be found, that is
[tex]\frac{4}6}[/tex] = [tex]\frac{10}{RT}[/tex] ( cross- multiply )
4RT = 60 ( divide both sides by 4 )
RT = 15
Hence
perimeter of ΔRST = 6 + 12 + 15 = 33 units
The perimeter of triangle RST which is similar to triangle MNO is: C. 33 units.
The perimeter of a triangle = sum of all its 3 sides.
Since triangles MNO and RST are similar triangles, then their corresponding side lengths are proportional to each other.
This means that:
MN/RS = MO/RT = NO/ST
Find RT using MN/RS = MO/RT:
4/6 = 10/RT
RT = (10×6)/4
RT = 15 units.
Perimeter of triangle RST = RS + ST + RT = 6 + 12 + 15 = 33 units.
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