Answer:
356.484 g.
Explanation:
M = (no. of moles of NaCl)/(volume of the solution (L))
M = 6.10 M, volume of the solution = 1.0 L.
∴ No. of moles of NaCl = (M)(volume of the solution (L)) = (6.10 M)(1.0 L) = 6.10 mol.
∵ no. of moles of NaCl = (mass of NaCl)/(molar mass of NaCl)
∴ Mass of NaCl = (no. of moles of NaCl)(molar mass of NaCl) = (6.10 mol)(58.44 g/mol) = 356.484 g.
NaCl mass : 356.85 grams
Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc
Mole
The mole itself is the number of particles contained in a substance amounting to 6.02.10²³
Mole can also be sought if the amount of substance mass and its molar mass is known
[tex] \large {\boxed {\boxed {\bold {mol = \frac {mass} {molar \: mass}}}} [/tex]
known
M NaCl = 6.10 M
Volume = 1.00 L
asked
NaCl mass
solution
molar mass of NaCl: 23 + 35.5 = 58.5 g / mol
mole NaCl = gram / mass
mole NaCl = molarity x volume
mol of NaCl = 6.1 x 1
mole of NaCl = 6.1
NaCl mass = molar mass x mol
mass of NaCl = 58.5 x 6.1
mass of NaCl = 356.85 grams
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Keywords: mole, NaCl, volume, molarity
