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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each division expression with the correct quotient.

Drag the tiles to the correct boxes to complete the pairs Not all tiles will be used Match each division expression with the correct quotient class=

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Answer:

[tex]\frac{16x^2+48x}{8x} = 2x+6\\\frac{56x^2-14x}{7x} = 8x-2\\\frac{18x^2+15x}{3x}=6x+5\\\frac{20x^2-32x}{4x}=5x-8[/tex]

Step-by-step explanation:

We will solve the division one by one:

[tex]\frac{16x^2+48x}{8x} = \frac{8x(2x+6)}{8x} = 2x+6\\\frac{56x^2-14x}{7x}=\frac{7x(8x+2)}{7x}=8x+2\\\frac{18x^2+15x}{3x} =\frac{3x(6x+5)}{3x} = 6x+5\\\frac{20x^2-32x}{4x}=\frac{4x(5x-8)}{4x}=5x-8[/tex]

Answer with explanation:

a)

[tex]\dfrac{16x^2+48x}{8x}[/tex]

Since, both the terms in the numerator have a common factor as: 8x.

Hence, we take out common 8x from the numerator term and hence it could be written as:

[tex]\dfrac{8x(2x+6)}{8x}[/tex]

i.e.

[tex]=2x+6[/tex]

b)

[tex]\dfrac{56x^2-14x}{7x}[/tex]

Since, both the terms in the numerator have a common factor as: 14x.

Hence, we take out common 14x from the numerator term and hence it could be written as:

[tex]=\dfrac{14x(4x-1)}{7x}\\\\=2(4x-1)\\\\=8x-2[/tex]

c)

[tex]\dfrac{(18x^2+15x)}{3x}[/tex]

Since, both the terms in the numerator have a common factor as: 3x.

Hence, we take out common 3x from the numerator term and hence it could be written as:

[tex]=\dfrac{3x(6x+5)}{3x}\\\\=6x+5[/tex]

d)

[tex]\dfrac{20x^2-32x}{4x}[/tex]

Since, both the terms in the numerator have a common factor as: 4x.

Hence, we take out common 4x from the numerator term and hence it could be written as:

[tex]=\dfrac{4x(5x-8)}{4x}\\\\=5x-8[/tex]

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