Respuesta :
That would be 1/16 which is 6.25%. The offspring have to be rryy.
There are 2 ways of thinking about this and other dihybrid crosses
—> the ratio of different genotypes is (9:3:3:1) for a dihybrid cross so the probability of wrinkled and green offspring is 1/16 (9+3+3+1=16)
—-> we can think of them as 2 monohybrid crosses. One RrxRr and one YyxYy. The probability of getting wrinkled(rr) is 1/4. The probability of getting green(yy) is 1/4. So the probability of wrinkled AND green is 1/4*1/4=1/16
There are 2 ways of thinking about this and other dihybrid crosses
—> the ratio of different genotypes is (9:3:3:1) for a dihybrid cross so the probability of wrinkled and green offspring is 1/16 (9+3+3+1=16)
—-> we can think of them as 2 monohybrid crosses. One RrxRr and one YyxYy. The probability of getting wrinkled(rr) is 1/4. The probability of getting green(yy) is 1/4. So the probability of wrinkled AND green is 1/4*1/4=1/16
Answer: 1/16.
Explanation:
Mendel explains the concept of dominance, laws of independent assortment and the laws of segregation by working on the plant Pisum sativum. Mendel is known as the father of genetics.
The dihybrid cross includes the two cross at a time. The round and yellow seeds has been crossed with the wrinkled and green seeds. By crossing the probability of obtaining the green and wrinkled seeds is 1/16. The sparate cross of round and wrinkled seeds, yellow and green seeds - the probability of gettting the recessive trait is 1/4. The combined probability is 1/4 × 1/4 = 1/16.
Thus, the answer is 1/16.
