Respuesta :
Answer:
The current in any one of the resistors is 1 A.
Explanation:
It is given that, four 20 ohm resistors are connected in parallel. In parallel combination of resistors, the voltage across each and every resistor is same while the current divides. The equivalent resistance of all resistors is given by :
[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\dfrac{1}{R_4}[/tex]
[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{20\ \Omega}+\dfrac{1}{20\ \Omega}+\dfrac{1}{20\ \Omega}+\dfrac{1}{20\ \Omega}[/tex]
[tex]R_{eq}=5\ \Omega[/tex]
Current flowing in the entire circuit can be calculated using Ohm's law as :
Current, [tex]I=\dfrac{V}{R_{eq}}[/tex]
[tex]I=\dfrac{20\ V}{5\ \Omega}[/tex]
I = 4 A
Since, in parallel combination current divides. So, current flowing in all four resistor divides and is 1 A. Hence, this is the required solution.
The current in any one of the resistors is equal to: B) 4.0 A
Given the following data:
- Resistors = 20 Ohm.
- Number of resistors = 4.
- Voltage = 20 Volt.
To determine the current in any one of the resistors:
How to determine the current.
First of all, we would calculate the total effective resistance of the four (4) resistors that are connected in parallel:
[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} \\\\\frac{1}{R_T} = \frac{1}{20} + \frac{1}{20} + \frac{1}{20} + \frac{1}{20}\\\\\frac{1}{R_T} = \frac{4}{20} \\\\4R_T=20\\\\R_T=\frac{20}{4}[/tex]
Total resistance = 5 ohms.
For the current:
Applying Ohm's law, we have:
[tex]I = \frac{V}{R} \\\\I = \frac{20}{5}[/tex]
Current, I = 4 Amperes.
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