For this case we have that by definition, the volume of a square base pyramid is given by:
[tex]V = \frac {1} {3} * L ^ 2 * h[/tex]
Where:
L: It's the side of the square base
h: It's the height of the pyramid
According to the data we have:
[tex]L = 54\m\\h = 260\m[/tex]
Substituting in the formula:
[tex]V = \frac {1} {3} * (54) ^ 2 * 260\\V = \frac {1} {3} * 2916 * 260\\V = \frac {1} {3} * (758160)\\V = 252,720 \ m ^ 3[/tex]
Thus, the volume of the building is [tex]252,720 \ m ^ 3[/tex]
Answer:
[tex]252,720 \ m ^ 3[/tex]
