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When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+MgCl2(aq)→2AgCl(s)+Mg(NO3)2(aq) What mass of silver chloride can be produced from 1.50 L of a 0.118 M solution of silver nitrate?

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daienrode
Answer: 16.76 grams of silver chloride


Use the molarity formula to get the moles of silver nitrate. M = mol/liters

Then use the balanced equation to do mole to mole ratio to go from silver nitrate to silver chloride.

Then use the molar mass to go from the moles of Silver chloride to the grams of silver chloride.

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