Respuesta :

carlosego

For this case we have that by definition, the distance between two points is given by:

[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]

We have the following points:

[tex](x_ {1}, y_ {1}): (- 3,4)\\(x_ {2}, y_ {2}) :( 21,11)[/tex]

We replace:

[tex]d = \sqrt {(21 - (- 3)) ^ 2+ (11-4) ^ 2}\\d = \sqrt {(21 + 3) ^ 2 + (11-4) ^ 2}\\d = \sqrt {(24) ^ 2 + (7) ^ 2}\\d = \sqrt {576 + 49}\\d = \sqrt {625}\\d = 25[/tex]

Thus, the distance between the two points is 25 units.

Answer:

25

imlittlestar

Answer:

The distance is 25 units

Step-by-step explanation:

Points to remember

Distance formula

Length of a line segment with end points (x1, y1) and (x2, y2) is given by,

Distance = √[(x2 - x1)² + (y2 - y1)²]

To find the distance between given points

Here (x1, y1) = (-3, 4) and (x2, y2) = (21, 11)

Distance = √[(x2 - x1)² + (y2 - y1)²]

= √[(21 - -3)² + (11 - 4)²]

= √[(21 +3)² + (11 - 4)²]

= √[24² + 7²]

 = √(576 + 49)

 = √625

 =25

Therefore the distance is 25 units

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