Respuesta :

Answer:

[tex]\sqrt{98}[/tex]

Step-by-step explanation:

Using the distance formula

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (3, - 5)

d = [tex]\sqrt{(3+4)^2+(-5-2)^2}[/tex]

  = [tex]\sqrt{7^2+(-7)^2}[/tex]

  = [tex]\sqrt{49+49}[/tex]

  = [tex]\sqrt{98}[/tex]

C= [tex]\sqrt{98}[/tex]

What happens when you square a square root?

We could say that the square root or the square cancel each other out. They are a inverse of each other. If we have the number written with the index two ( squared) then taking the square root simply means that we leave out the two ( this only applies on the positive numbers ).

How to figure out square roots?

  • Start by i = 1, if i * i = n, then i it is the square root of n as n is the perfect square.
  • if i * i > n, it means square root must lie between (i-1, i), let’s call them (low, high)
  • Apply binary search in the range (low, or high). Find mid of (low, high):

Using the distance formula

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (3, - 5)

[tex]d= \sqrt{(3+4)^{2} +(-5-2)^{2}} \\\\= \sqrt{7^{2} + (-7)^{2}} \\\\= \sqrt{49+49} \\\\=\sqrt{98}[/tex]

Learn more about  square root here https://brainly.com/question/3120622

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