What is the distance between the points (–4, 2) and (3, –5)?

Answer:
[tex]\sqrt{98}[/tex]
Step-by-step explanation:
Using the distance formula
with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (3, - 5)
d = [tex]\sqrt{(3+4)^2+(-5-2)^2}[/tex]
= [tex]\sqrt{7^2+(-7)^2}[/tex]
= [tex]\sqrt{49+49}[/tex]
= [tex]\sqrt{98}[/tex]
C= [tex]\sqrt{98}[/tex]
We could say that the square root or the square cancel each other out. They are a inverse of each other. If we have the number written with the index two ( squared) then taking the square root simply means that we leave out the two ( this only applies on the positive numbers ).
Using the distance formula
with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (3, - 5)
[tex]d= \sqrt{(3+4)^{2} +(-5-2)^{2}} \\\\= \sqrt{7^{2} + (-7)^{2}} \\\\= \sqrt{49+49} \\\\=\sqrt{98}[/tex]
Learn more about square root here https://brainly.com/question/3120622
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