Answer:
(3x² - 2)(x² + 5)
Step-by-step explanation:
Given
3[tex]x^{4}[/tex] - 2x² + 15x² - 10
Factor the first/second and third/fourth terms
= x²(3x² - 2) + 5(3x² - 2) ← factor out (3x² - 2) from each term
= (3x² - 2)(x² + 5)
Answer:
[tex](x^2+5)(3x^2-2)[/tex]
Step-by-step explanation:
The polynomial is
[tex]3x^4-2x^2+15x^2-10[/tex]
You can group the first and third term and the second and last term
[tex]3x^4+15x^2-2x^2-10[/tex]
Factorize each pair
[tex]3x^4+15x^2-2x^2-10[/tex]
[tex]3x^2(x^2+5)-2(x^2+5)[/tex]
Finally, you can factor the [tex](x^2+5)[/tex] and obtain
[tex](x^2+5)(3x^2-2)[/tex]
Then, the answer is (x2 + 5)(3x2 – 2)
