Mixed molarity = 0.25 M
Osmotic pressure solution: 6.15 atm
Osmotic pressure is the minimum pressure given to the solution so that there is no osmotic displacement from a more dilute solution to a more concentrated solution.
General formula:
[tex]\large{\boxed {\bold {\pi \: = \: M \: x \: R \: x \: T}}}[/tex]
π = osmotic pressure (atm)
M = solution concentration (mol / l)
R = constant = 0.08205 L atm mol-1 K-1
T = Temperature (Kelvin)
Mixing solution
To find the molarity of the mixed solution we can use the following formula:
Vc. Mc = V1.M1 + V2.M2
where
Mc =Mixed molarity
Vc = mixed volume
Mr. NaCl = 58.5
Mr. Dextrose = C₆H₁₂O₆ = 180
mole NaCl = gram / Mr
mole NaCl = 1.75 / 58.5 = 0.03
Dextrose mole = 40/180 = 0.22
Assuming 1 liter of solution
M mixture = mole NaCl + mole dextrose / 1 liter
M mixture = 0.03 + 0.22 / 1 L
M mix = 0.25 M
T = 25 + 273 = 298 K
The osmosis pressure of the solution becomes:
π = 0.25. 0.0825. 298 = 6.15 atm
The osmotic pressure https://brainly.com/question/8195553
Grade: Senior High School
Subject: Chemistry
Chapter: Colligative property
Keywords: osmotic pressure, molarity, mole,dextrose, NaCl
