Answer: (a) [tex]\dfrac{1}{7}[/tex] (b) [tex]\dfrac{12}{35}[/tex]
Step-by-step explanation:
Given: Number of white balls : 6
Number of red balls = 9
Total balls = 15
(a) The probability that both balls are white is given by :-
[tex]\dfrac{^6C_2}{^{15}{C_2}}\\\\=\dfrac{\dfrac{6!}{2!(6-2)!}}{\dfrac{15!}{2!(15-2)!}}=\dfrac{1}{7}[/tex]
∴ The probability that both balls are white is [tex]\dfrac{1}{7}[/tex] .
(b) The probability that both balls are red is given by :-
[tex]\dfrac{^9C_2}{^{15}C_2}\\\\=\dfrac{\dfrac{9!}{2!(9-2)!}}{\dfrac{15!}{2!(15-2)!}}=\dfrac{12}{35}[/tex]
∴ The probability that both balls are red is [tex]\dfrac{12}{35}[/tex] .