Answer:
32) A. 1
33) E. 2
34) C. 12
35) D. Sb₄O₆
Explanation:
32. N₂O₅ + __H₂O → 2HNO₃
left side: 2 H , 2 N, 6 O
right side: 2 H, 2 N, 6 O
Nothing needs to change, so put a 1
33. P₂O₅ + 3H₂O → __H₃PO₄
left side: 6 H, 2 P, 8 O
right side: 3 H, 1 P, 4 O
everything on the right needs to double, so put a 2
34. Sb₄O₆ + __HCl → 4SbCl₃ + 6H₂O
left side: 4 Sb, 6 O, 1 H, 1 Cl
right side: 4 Sb, 6 O, 12 H, 12 Cl
the H and Cl on the left both need to be multiplied by 12, so put a 12
35. ____ + 4NaOH → 4NaSbO₂ + 2H₂O
left side: 4 Na, 4 O, 4 H
right side: 4 Na, 10 O, 4 H, 4 Sb
the left side needs 6 more O and 4 Sb, so add Sb₄O₆
