Answer:
[tex]x^2 +(y-8)^2=64[/tex]
Step-by-step explanation:
The equation of the circle with center at point [tex](x_0,y_0)[/tex] and radius r is
[tex](x-x_0)^2+(y-y_0)^2=r^2[/tex]
In your case,
- [tex]x_0=0[/tex]
- [tex]y_0=8[/tex]
- [tex]r=8[/tex]
So, the equation of the circle with center at (0,8) and radius r=8 is
[tex](x-0)^2+(y-8)^2=8^2\\ \\x^2 +(y-8)^2=64[/tex]
