[tex]\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\pi \theta r^2 }{360}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ \cline{1-1} r=6\\ \theta =55 \end{cases}\implies A=\cfrac{\pi (55)(6)^2}{360}\implies A=\cfrac{11\pi }{2} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 17.28~\hfill[/tex]
