Answer:
Angle the wire make with respect to the magnetic field is 30°.
Explanation:
It is given that,
Length of wire, L = 0.6 m
Current flowing in the wire, I = 2 A
Magnetic field strength, B = 0.3 T
It is placed in the magnetic field. It will experience a force of, F = 0.18 N. We need to find the angle the wire make with respect to the magnetic field. The force acting on the wire is given by :
[tex]F=I(L\times B)[/tex]
[tex]F=ILB\ sin\theta[/tex]
[tex]\theta=sin^{-1}(\dfrac{F}{ILB})[/tex]
[tex]\theta=sin^{-1}(\dfrac{0.18\ N}{2\ A\times 0.6\ m\times 0.3\ T})[/tex]
[tex]\theta=30^{\circ}[/tex]
So, the angle the wire make with respect to the magnetic field is 30°. Hence, this is the required solution.
