Answer:
The flux of the net electric field is [tex]2.26\times10^{5}\ Nm^2/C[/tex]
Explanation:
Given that,
Charge [tex]q= 2.00 \mu C[/tex]
Electric field E = 100 N/C i
Radius R = 10.0 cm
We need to find the flux. It can be calculate using Gauss's law
The flux of the net electric field
[tex]\phi=\dfrac{q}{\epsilon_{0}}[/tex]
[tex]\phi=\dfrac{2.00\times10^{-6}}{8.85\times10^{-12}}[/tex]
[tex]\phi=2.26\times10^{5}\ Nm^2/C[/tex]
Hence, The flux of the net electric field is [tex]2.26\times10^{5}\ Nm^2/C[/tex]
