Respuesta :

hazelh441

Answer:

Q1. The solution for the quadratic equation on a graph is same as the value of x-intercept(zeros)

Q2. discriminant(b^2-4ac) when y=ax^2 + bx + c

there are 3 situations:

1. discriminant > 0 → 2 real solutions(2 x-intercepts/zeros)

2. discriminant = 0 → 1 real solution(1 x-intercept/zero)

3. discriminant < 0 → 0 real solution(0 x-intercept/zero) → also 2 imaginary solution

Hope it helped!

Step-by-step explanation:

luisejr77

Answer:

1) You find the solution by identifying the x-intercepts.

2) Possible real solutions:

- One real solution.

- Two distinct real solutions.

Step-by-step explanation:

1) The graph of a quadratic equation is a parabola.

By definition, the x-intercepts (Where [tex]y=0[/tex]) are the solutions of the quadratic equation .

2) Given a quadratic equation [tex]ax^2+bx+c=0[/tex], you can know the number of real solutions by using this formula to find the Discriminant :

[tex]D=b^2-4ac[/tex]

If  [tex]D=0[/tex], then there is one real solution with multiplicity two.

If  [tex]D>0[/tex], then there are two distinct real solutions.

On a graph:

-If the graph has two x-intercepts, then the quadratic equation has two real solutions.

 -If the graph has one x-intercept , then the quadratic equation has one real solution.